Indian Wells, 11 March (H.S.):

World No. 1 Aryna Sabalenka of Belarus delivered a commanding performance against fellow Grand Slam champion Naomi Osaka of Japan, winning 6-2, 6-4 on Tuesday to advance to the Indian Wells Open quarterfinals.

Sabalenka unleashed 31 winners and 8 aces, breaking Osaka's serve twice in the first set for a swift takeover. In the second, Osaka mounted a fightback but couldn't breach Sabalenka's robust service game; the Belarusian saved both break points and clinched a 4-3 edge with a stunning forehand winner. She now faces the winner of Amanda Anisimova vs. Victoria Mboko.This marked only their second meeting—Osaka prevailed in 2018 en route to her first major title.

Post-match, Sabalenka credited her court variation for keeping Osaka off-balance at crucial junctures.Gibson Stuns Paolini in ThrillerMeanwhile, Australian qualifier Talia Gibson, ranked 112, upset seventh seed Jasmine Paolini 7-5, 2-6, 6-1, firing 42 winners in her first career Top-10 win. The 21-year-old seized the decider with aggressive play after Paolini's second-set resurgence. Gibson next meets the Linda Noskova vs. Alexandra Eala victor, buoyed by her emotional breakthrough.

---------------

Hindusthan Samachar / Jun Sarkar